Relative masses & the mole: OCR A A-level Chemistry

Define the two OCR-required relative masses and explain the carbon-12 standard.

OCR A · Amount of substance · Notes and practice

Learn → practise → check

Relative masses & the mole

4 practice questions

Relative isotopic and atomic masses

Learning goalDefine the two OCR-required relative masses and explain the carbon-12 standard.

🔓 CRACK IT

Atoms are too small for ordinary gram measurements to be convenient. Relative masses compare them with a shared reference: one-twelfth of the mass of one carbon-12 atom.

Relative isotopic mass describes an atom of one particular isotope. Relative atomic mass, Aᵣ, is a weighted mean for the element, allowing for its isotope abundances.

Because each relative mass is a ratio of two masses, it has no unit. Keep that separate from molar mass, which is normally expressed in g mol⁻¹. The definitions below give the precise exam wording.

Use the Aᵣ values on your supplied Periodic Table, which gives values to one decimal place, for example Cl = 35.5. Use the exact data given in a question, including any more precise isotopic masses.

Relative isotopic mass
The mass of an atom of an isotope compared with one-twelfth of the mass of an atom of carbon-12.
Relative atomic mass, Ar
The weighted mean mass of an atom of an element compared with one-twelfth of the mass of an atom of carbon-12.
EXAM TRAPFor Ar, “average” alone misses the weighting. Include both weighted mean and the carbon-12 comparison.

🧪 TEST IT

Work on paper. Attempt each question before opening its answer. These are original CrackingChem questions, written in OCR A style.

Quick check 1

(a) State the definition of relative isotopic mass. [2 marks]

(b) State the definition of relative atomic mass, Ar. [2 marks]

Total: 4 marks

Show answer & marking points

(a) Relative isotopic mass: the mass of an atom of an isotope compared with one-twelfth of the mass of an atom of carbon-12: atom of an isotope [1]; carbon-12 comparison [1].

(b) Relative atomic mass: the weighted mean mass of an atom of an element compared with one-twelfth of the mass of an atom of carbon-12: weighted mean [1]; carbon-12 comparison [1].

Marking note: For Ar, average on its own is not enough. OCR requires weighted mean. Do not attach a unit to either relative mass.

✓ DONE WHENDefine the two required relative masses and explain the carbon-12 standard.

Calculate relative molecular and formula masses

Learning goalCount every atom in a formula, including brackets, and leave relative values unitless.

🔓 CRACK IT

A formula is an atom-counting instruction. To find a relative molecular or formula mass, add the Aᵣ contribution of every atom in the formula.

  1. Write down how many atoms of each element are present.
  2. Multiply the count of each element by its Aᵣ.
  3. Add the contributions.

Brackets are the usual trap. In Al₂(SO₄)₃, the outside 3 multiplies both S and O, giving Al₂S₃O₁₂. It does not multiply the Al.

Use relative molecular mass for separate molecules and relative formula mass for a formula describing a giant structure. Give no unit for a relative mass. The same numerical value used as a molar mass has units of g mol⁻¹.

Relative mass = sum of all Ar values in the formula

Ar relative atomic mass; no unit.

Worked example

Brackets and subscripts

Calculate the relative formula mass of Ca(NO3)2. Use Ca 40.1, N 14.0 and O 16.0.

Worked answer

Relative molecular/formula mass = sum of the Aᵣ contributions of every atom

QuantityCaNO
Number of atoms126
Ar40.114.016.0
ContributionContribution = atom count × Aᵣ
40.1
Contribution = atom count × Aᵣ
28.0
Contribution = atom count × Aᵣ
96.0
40.1 + 28.0 + 96.0 = 164.1
Relative formula mass = 164.1.
EXAM TRAPThe outside 2 multiplies both N and O. It does not multiply Ca.

🧪 TEST IT

Work on paper. Attempt each question before opening its answer. These are original CrackingChem questions, written in OCR A style.

Exam-style question 2

Use H = 1.0, C = 12.0, N = 14.0, O = 16.0 and Mg = 24.3.

(a) Calculate Mr of C2H5OH. [2 marks]

(b) Calculate the relative formula mass of Mg(NO3)2. [3 marks]

(c) State why neither answer has a unit. [1 mark]

Total: 6 marks

Show answer & marking points

Relative molecular/formula mass = sum of the Aᵣ contributions of every atom

(a) Mr(C2H5OH) = (2 × 12.0) + (6 × 1.0) + 16.0 [1] = 46.0 [1].

(b) Relative formula mass of Mg(NO3)2 = 24.3 + (2 × 14.0) + (6 × 16.0) [2] = 148.3 [1].

(c) Relative masses are comparison values, so they have no unit. [1]

✓ DONE WHENCount every atom in a formula, including brackets, and leave relative values unitless.

Relative mass and molar mass

Learning goalDistinguish relative mass from molar mass and use the correct units.

🔓 CRACK IT

Relative mass and molar mass often have the same numerical value, but they describe different quantities.

Relative molecular or formula mass is a comparison with the carbon-12 reference and has no unit. Molar mass, M, is the mass of one mole and is usually given in g mol⁻¹.

For water, Mᵣ = 18.0 and M = 18.0 g mol⁻¹. Use the molar mass when calculating n = m/M, with mass in grams. Do not put g mol⁻¹ on Mᵣ itself.

QuantityMeaningUnit
ArRelative mass for an element’s atomsNone
Mr / relative formula massRelative value for a molecule or formula unitNone
MMass per mole of the stated substanceg mol−1
Worked example

Water: the same number, different quantities

Use H 1.0 and O 16.0 to compare Mr(H2O), M(H2O) and the mass of 2.00 mol H2O.

Worked answer

Mr(H2O) = 2(1.0) + 16.0 = 18.0
M(H2O) = 18.0 g mol−1
m = n × M
m = 2.00 × 18.0 = 36.0 g
The relative mass has no unit; the molar mass is in g mol−1; the sample mass is in g.
EXAM TRAPRead the symbol before choosing a unit. Mr = 18.0, but M = 18.0 g mol−1.

🧪 TEST IT

Work on paper. Attempt each question before opening its answer. These are original CrackingChem questions, written in OCR A style.

Exam-style question 3

Use Ca = 40.1, O = 16.0 and H = 1.0 for calcium hydroxide, Ca(OH)2.

(a) Calculate its relative formula mass. [2 marks]

(b) State its molar mass, including the unit. [1 mark]

(c) Explain why the two numerical values are equal but the units are different. [2 marks]

Total: 5 marks

Show answer & marking points

(a) Relative formula mass = 40.1 + (2 × 16.0) + (2 × 1.0) [1] = 74.1 [1].

(b) M(Ca(OH)2) = 74.1 g mol−1. [1]

(c) The numerical value is the same because one mole has a mass in grams equal to the relative formula mass [1]. Relative formula mass is unitless, whereas molar mass is mass per mole in g mol−1 [1].

✓ DONE WHENDistinguish relative mass from molar mass and use the correct units.

The mole and Avogadro constant

Learning goalExplain amount of substance and name the entity counted by the Avogadro constant.

🔓 CRACK IT

THE EXACT DEFINITION

One mole contains exactly 6.02214076 × 1023 specified entities. The exact Avogadro constant is 6.02214076 × 1023 mol−1. For calculations, use the supplied rounded value, NA = 6.02 × 1023 mol−1.

A mole is a unit for measuring amount of substance, rather like a dozen is a unit for counting items. You can have one mole, two moles or half a mole.

The mole and the Avogadro constant do different jobs. mol is the unit; NA tells you how many specified particles there are per mole. Think of “dozen” and 12: the word names the counting unit, while the number tells you how many items it contains.

Use NA = 6.02 × 10²³ mol⁻¹, rounded to three significant figures. So 1 mol contains approximately 6.02 × 10²³ specified particles. Use a different value if a question explicitly supplies one.

The amount of substance has symbol n and unit mol. Name what you are counting: atoms, molecules, formula units, ions or electrons. One mole of each contains the same number of entities, but their masses differ. One mole of O₂ molecules contains two moles of oxygen atoms.

SubstanceBasic entity
NeAtom
O2Molecule
NaClFormula unit
Al3+Ion
N = nNA; n = N/NA

N number of the specified particles; a count with no unit; NA Avogadro constant, 6.02 × 10²³ mol⁻¹; n amount of the specified substance or particles, in mol.

EXAM TRAPWrite the formula or entity beside n and N. “Particles” alone is too vague for a final answer.

🧪 TEST IT

Work on paper. Attempt each question before opening its answer. These are original CrackingChem questions, written in OCR A style.

Quick check 4

(a) State the symbol and unit for amount of substance. (2 marks)

(b) Explain the difference between a mole and the Avogadro constant. (2 marks)

Total: 4 marks

Show answer & marking points

(a) Symbol n [1]; unit mol. [1]

(b) The mole is the unit for amount of substance. [1] The Avogadro constant is the number of specified entities per mole and has unit mol−1. [1] Its exact value is 6.02214076 × 1023 mol−1; the OCR A calculation value, 6.02 × 1023 mol−1, is rounded. The exact numerical value is not required for these questions.

✓ DONE WHENExplain amount of substance and name the entity counted by the Avogadro constant.

Download this topic

More amount of substance revision

Complete OCR A amount of substance topic · All OCR A topics

Make revision stick

Read an explanation, work through an example, then try a question before revealing its answer. Use the free videos when you need to see the method in action.

Create a free account to save questions and track progress, or keep exploring without signing in. Join the free Sunday live lessons for more practice.

Nuclide notation