Ionic bonding & formulae: OCR A A-level Chemistry

Balance charges and use correct brackets and smallest ratios.

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Ionic bonding & formulae

11 practice questions

Ionic formulae and common ions

Learning goalBalance charges and use correct brackets and smallest ratios.

🔓 CRACK IT

An ionic formula must have no overall charge. Choose the smallest whole-number ratio of ions that makes the positive and negative charges balance.

For example, one 2+ ion needs two 1- ions. Use the charges to find the ratio, then write the subscripts in the formula.

A compound ion stays together as a group. If you need more than one of that ion, put brackets around its formula before adding the subscript. The table below gives common ions to recognise.

Ionic formula
The smallest whole-number ratio of ions giving zero overall charge.
Group / ionCharge or formula
Group 11+
Group 22+
Group 162−
Group 171−
NitrateNO3-
CarbonateCO32-
SulfateSO42-
HydroxideOH-
AmmoniumNH4+
ZincZn2+
SilverAg+
Worked example

Calcium nitrate

Write the formula from Ca2+ and NO3-.

Worked answer

  1. One Ca2+ ion has charge +2.
  2. Two nitrate ions give charge −2.
  3. Keep each nitrate ion intact and use brackets.
Ca(NO3)2
EXAM TRAPUse brackets only when more than one compound ion is required. Simplify Ca2O2 to CaO; never change the internal formula of a compound ion.

🧪 TEST IT

Work on paper. Attempt each question before opening its answer. These are original CrackingChem questions, written in OCR A style.

Exam-style question 1

Complete the table of OCR A ions. [7]

Ion nameFormula and charge
Nitrate…
Carbonate…
Sulfate…
Hydroxide…
Ammonium…
Zinc…
Silver…

Total: 7 marks

Show answer & marking points

NO3- nitrate [1]; CO32- carbonate [1]; SO42- sulfate [1]; OH- hydroxide [1]; NH4+ ammonium [1]; Zn2+ zinc [1]; Ag+ silver [1]

Exam-style question 2

Write the formula of each compound. Every formula must be neutral and in the smallest whole-number ratio. [6]

PartCompoundFormula
aAluminium oxide…
bCalcium nitrate…
cAmmonium sulfate…
dMagnesium hydroxide…
eZinc carbonate…
fSilver nitrate…

(g) State when brackets are required around a compound ion. [1]

Total: 7 marks

Show answer & marking points

Aluminium oxide Al2O3 [1]; calcium nitrate Ca(NO3)2 [1]; ammonium sulfate (NH4)2SO4 [1].

Magnesium hydroxide Mg(OH)2 [1]; zinc carbonate ZnCO3 [1]; silver nitrate AgNO3 [1].

Use brackets only when more than one of a compound ion is needed, so the subscript applies to the whole ion [1]

✓ DONE WHENEvery formula is neutral, simplified and uses brackets correctly.

Ionic bonding and electron origin

Learning goalSeparate ion formation from ionic attraction and construct electron-origin diagrams.

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There are two ideas to keep separate. Electron transfer makes the ions. The attraction between the resulting positive and negative ions is the ionic bonding.

A metal atom loses electrons and becomes a positive ion. A non-metal atom gains electrons and becomes a negative ion. In a giant ionic lattice, each ion attracts surrounding ions of the opposite charge.

In a dot-and-cross diagram, use dots and crosses consistently to show where the electrons came from. Show outer-shell electrons, put each ion in square brackets and write its charge outside. Check both electron totals and the ratio of ions.

Ionic bonding
Electrostatic attraction between positive and negative ions.
EXAM TRAPA transfer arrow represents a process, not the ionic bond itself.

🧪 TEST IT

Work on paper. Attempt each question before opening its answer. These are original CrackingChem questions, written in OCR A style.

Quick check 3

(a) State the precise OCR A definition of ionic bonding. [2 marks]

(b) Explain why electron transfer is not itself the ionic bond. [2 marks]

Total: 4 marks

Show answer & marking points

(a) Ionic bonding is the electrostatic attraction [1] between positive and negative ions [1]. [2]

(b) Electron transfer is the process that forms the ions [1]; the bond is the attraction between the ions after transfer [1]. [2]

Exam-style question 4

Draw a dot-and-cross diagram for magnesium chloride, MgCl2. Show outer-shell electrons only, electron origin, square brackets, charges and complete outer shells. [5 marks]

Total: 5 marks

Show answer & marking points

One Mg2+ ion and two Cl- ions, all bracketed and correctly charged [2].

Each chloride ion has eight outer-shell electrons [1], with one electron on each chloride shown as transferred from Mg [1]. Magnesium has lost two electrons in total [1]. [5]

Exam-style question 5

Sodium forms Na+ ions and oxygen forms O2- ions.

(a) Deduce the formula of sodium oxide. [1 mark]

(b) Draw a complete electron-origin diagram for sodium oxide. Show all ions, brackets, charges and outer-shell electrons. [6 marks]

Total: 7 marks

Show answer & marking points

(a) Two Na+ ions are needed for one O2- ion, so the formula is Na2O [1]. [1]

(b) Two bracketed Na+ ions and one bracketed O2- ion [2]; oxide has eight outer-shell electrons [1], including two electrons shown as transferred from sodium [2]; electron totals and charges are consistent with Na2O [1]. [6]

Exam-style question 6

Main-group elements X and Y form X3+ and Y2- ions with complete octets. X has three outer-shell electrons and Y has six before ion formation.

(a) Deduce the formula of the compound formed. [2 marks]

(b) State the total number of electrons transferred when one formula unit forms. [2 marks]

(c) Draw a complete electron-origin diagram for one formula unit. Show the smallest ion ratio, complete outer shells, brackets and charges. [6 marks]

Total: 10 marks

Show answer & marking points

(a) Charge balance requires 2 × (+3) and 3 × (−2), so the formula is X2Y3 [2]. [2]

(b) Two X atoms each lose three electrons, so six electrons are transferred in total [2]. [2]

(c) Two bracketed X3+ ions and three bracketed Y2- ions [2]; each Y2- has eight outer-shell electrons [1], with two transferred electrons shown on each [2]; all charges and the 2:3 ratio are correct [1]. [6]

Exam-style question 7

Stretch note: This question connects Atomic Structure II electron configurations with ionic formulae, electron origin and conductivity. Atom X has electron configuration 1s2 2s2 2p6 3s2. Atom Y has electron configuration 1s2 2s2 2p5.

(a) Identify X and Y. [2 marks]

(b) State the ions formed by X and Y. [2 marks]

(c) Deduce the formula of the compound formed. [1 mark]

(d) Draw a complete electron-origin diagram for the compound. [5 marks]

(e) Explain why the compound does not conduct as a solid but does conduct when molten. [2 marks]

Total: 12 marks

Show answer & marking points

(a) X has 12 electrons, so X is magnesium, Mg [1]. Y has 9 electrons, so Y is fluorine, F [1]. [2]

(b) Mg loses two electrons to form Mg2+ [1]; F gains one electron to form F- [1]. [2]

(c) One Mg2+ requires two F- ions, so the formula is MgF2 [1]. [1]

(d) One bracketed Mg2+ and two bracketed F- ions [2]; each fluoride has eight outer-shell electrons [1], including one electron shown as transferred from Mg [1]; final electron totals and charges are correct [1]. [5]

(e) In solid MgF2, ions are fixed and cannot carry charge [1]. When molten, the ions are mobile and carry charge [1]. [2]

✓ DONE WHENYour ionic diagram shows electron origin, correct electron totals, brackets and charges.

Giant ionic lattices and their properties

Learning goalExplain melting, solubility and conductivity using ions and their mobility.

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An ionic solid is a giant repeating arrangement of positive and negative ions. Strong electrostatic attractions act throughout the lattice, so a lot of energy is needed to separate the ions on melting.

For conductivity, ask whether charged particles can move. In the solid, the ions are held in fixed positions. When molten, the ions can move and carry charge.

Many ionic compounds dissolve in water, although not all do. If an ionic compound forms an aqueous solution, its mobile ions can carry charge. Do not explain ionic conductivity using moving electrons.

Higher ion charges and smaller ionic radii generally strengthen the electrostatic attraction. For the same charges, smaller ions let the centres of opposite ions get closer together. Stronger attractions need more energy to overcome, so the melting point tends to be higher. Compare similar lattice arrangements and change one factor at a time.

Giant ionic lattice
A regular repeating arrangement of oppositely charged ions strongly attracted in all directions.
PropertyExplanation
High melting / boiling pointsMany strong electrostatic attractions throughout the lattice require much energy to overcome.
Solid does not conductIons are fixed; no mobile charge carriers.
Molten or dissolved sample conductsIons are mobile and carry charge.
SolubilityOften soluble in water, but not always: new solvent-ion attractions must compensate for attractions disrupted.
EXAM TRAPMolten ionic compounds conduct through mobile ions, not delocalised electrons. A charged ion does not automatically make every ionic compound soluble.
Worked example

Comparing ion charges: MgO and NaF

MgO and NaF have similar ion sizes and comparable lattice arrangements. Why does MgO have the higher melting point?

Worked answer

  1. Both have giant ionic lattices. MgO contains Mg²⁺ and O²⁻; NaF contains Na⁺ and F⁻.
  2. The ion sizes are similar, so focus on charge: the ions in MgO have larger charges.
  3. The electrostatic attractions between opposite ions are stronger in MgO.
  4. More energy is needed to overcome these attractions on melting.
Higher charges → stronger electrostatic attraction → more energy → higher melting point.
Worked example

Comparing ion sizes: NaCl and KCl

NaCl and KCl have the same ion charges and comparable lattice arrangements. Na⁺ is smaller than K⁺. Why does NaCl have the higher melting point?

Worked answer

  1. Both contain a 1+ metal ion and the same Cl⁻ ion, so charge does not explain the difference.
  2. The smaller Na⁺ ion allows the centres of opposite ions to be closer together.
  3. The electrostatic attraction between the ions is stronger in NaCl.
  4. More energy is needed to overcome these attractions on melting.
Smaller ions, with charge unchanged → stronger electrostatic attraction → higher melting point.

🧪 TEST IT

Work on paper. Attempt each question before opening its answer. These are original CrackingChem questions, written in OCR A style.

Quick check 8

Which has the higher melting point, CaO or KCl? Explain your answer. [3]

Total: 3 marks

Show answer & marking points

CaO has the higher melting point. Ca²⁺ and O²⁻ have larger charges than K⁺ and Cl⁻ [1], giving stronger electrostatic attractions between oppositely charged ions [1]. More energy is required to overcome these attractions when CaO melts [1].

Quick check 9

NaF and NaCl have comparable lattice arrangements. Explain why NaF has a higher melting point than NaCl. [3]

Total: 3 marks

Show answer & marking points

The smaller F⁻ ion allows the centres of opposite ions to be closer together [1]. With the same ion charges, electrostatic attractions are stronger in NaF [1], so more energy is needed to overcome them on melting [1].

Exam-style question 10

Sodium chloride forms a giant ionic lattice.

(a) Explain why sodium chloride has a high melting point. [2 marks]

(b) Explain why solid sodium chloride does not conduct electricity but molten sodium chloride does. [3 marks]

(c) Explain why aqueous sodium chloride conducts electricity. [1 mark]

(d) State whether all ionic compounds are soluble in water. [1 mark]

Total: 7 marks

Show answer & marking points

(a) NaCl has many strong electrostatic attractions between oppositely charged ions throughout a giant lattice [1]; much energy is required to overcome them [1]. [2]

(b) In solid NaCl, ions are fixed in position, so there are no mobile charge carriers [1]. When molten, the ions are mobile [1] and carry charge through the liquid [1]. [3]

(c) In aqueous NaCl, dissolved Na+ and Cl- ions are mobile and carry charge [1]. [1]

(d) Ionic compounds are often, but not always, soluble in water; solubility depends on whether new water-ion attractions compensate for separating the ions in the lattice [1]. [1]

Exam-style question 11

Each statement contains a chemistry error. Identify the error and write a corrected statement.

(a) The ionic bond is the transfer of electrons from a metal atom to a non-metal atom. [2 marks]

(b) Molten sodium chloride conducts because its electrons become free to move. [2 marks]

(c) Iodine melts because the covalent bond inside each I2 molecule is broken. [2 marks]

(d) All ionic compounds dissolve in water simply because their ions are charged. [2 marks]

Total: 8 marks

Show answer & marking points

(a) Transfer forms the ions [1]; ionic bonding is the electrostatic attraction between oppositely charged ions [1]. [2]

(b) The charge carriers are mobile Na+ and Cl- ions [1], not free electrons [1]. [2]

(c) Melting iodine overcomes intermolecular forces between I2 molecules [1]; the I-I covalent bonds remain intact [1]. [2]

(d) Ionic compounds are often but not always water-soluble [1]; solubility depends on the balance between attractions broken and new solvent-ion attractions formed [1]. [2]

✓ DONE WHENYou explain every property using the correct particles, attraction and mobility or energy.

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